Australian Greenhouse Gas Emissions

What the Australian  Government says:

PM claims Australia will meet Paris target ‘in a canter’ despite emissions climbing.

Morrison says rate of increase not as high as previous years and renewables investment will ensure Australia meets commitment

pm-claims-australia-will-meet-paris-target-in-a-canter-despite-emissions-climbing

What the government numbers say:

What the government numbers say when you look a little closer:

quarterly-update-australias-national-greenhouse-gas-inventory-march-2018

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Time in hours and minutes between two dates

Dates and times in Excel are stored as a date number, which is the number of days since 1 January 1900, with the value after the decimal point representing the time of day.

To calculate the number of hours between two dates we can simply subtract the two values and multiply by 24.  This returns a decimal value though.  If we want the time in hours and minutes (or hours minutes and seconds), things get a bit more complicated:

The screen-shot shows various alternatives for displaying the number of hours between the date/time in cell B3 and the start of the date in B2.

The first row shows the result of multiplying the date difference by 24.  This shows the correct result if formatted as a decimal, but if is formatted as time it shows the wrong value.

Microsoft recommends use of the Text function, with the format string “h:mm”.  Note that the format string overrides the cell format, so the returned text displays the same regardless of the cell number format.  This will work correctly for time differences up to 24 hours, but the display resets to zero after each 24hours, so the 36 hour time difference above displays as 12 hours.  This can be changed to display days, hours and minutes with the format string “d:h:mm”.

Another approach is to leave the time difference as a date number  and format to display as hours.  The default time format has the same problem as the “h:mm” format string, so 36 hours displays as 12, but it is possible to display the correct number of hours:

  • On the Home tab, select the Number Format dialogue.
  • Select Custom, then h:mm.
  • Edit in the Type box by putting square brackets around the h:  “[h]:mm”.
  • Time differences greater than 24 hours should now display correctly in hours and minutes (see cell F8 below).
  • It is possible to use the same approach with the Text function (Row 9 below).  Note that the time difference now displays in hours and minutes, regardless of the cell format.

Update 1 Oct 18: As noted by Doug Glancy in the comments, the [h]:mm:ss format is available from the format dialog. In my version (Office 365) it is at the end of the time formats, near the bottom of the custom format list.

Posted in Excel | Tagged , , , , | 4 Comments

New AS 3600 and RC Design Functions 8

A revised version of the Australian Concrete Structures code, AS 3600, was recently published, with many significant changes, including:

  • Changes to ULS reduction Factors
  • Creep and shrinkage
  • Curvature and deflection calculations
  • Crack width calculation and stress limits
  • Major  changes to shear and torsion capacity calculations

The new provisions will require changes to all my concrete design spreadsheets, starting with RC Design Functions, which has now been updated for all the changes listed above (but only the simplified shear design method at present).  In addition the creep and shrinkage functions have been updated to allow calculation to the FIB Model Code, 2010.

The revised spreadsheet can be downloaded  from:

RC Design Functions8.zip

More details of specific changes will be given in future posts, but as always if you have any questions on theory or application, please ask in  a comment.

Posted in Concrete, Newton, UDFs, VBA | Tagged , , , , , | Leave a comment

2 more Moves Through the Fair

I have just mended a broken link in the previous installment of “She moves Through the Fair”.

Here are two more, from Tir Eolas:

and Tara McNeill:

Posted in Bach | Tagged , , | 2 Comments

Arc-spline update

The input for the first version of the Arcspline function required the coordinates of the centre of each arc, as well as the angle of the tangents at each end of the arc.  I have now added a new version with simplified input in a 4 column range.

The new file may be downloaded from: IP2.zip

The required inputs are:

  • Row 1: XY coordinates of the start point
  • For each arc: XY  coordinates of the intersection point of the tangents at the ends of the arc, the arc radius, and the number of segments for each arc
  • Last row: XY coordinates of the end point

Options:

  • If the spline is a closed curve the end point may be omitted.
  • If the spline is not closed,  set the optional second argument (Closearc) to False.  In this case the end point must be provided.
  • The default return array is the coordinates of the spline curve.  If the third argument (Out) = 1, details of each arc will be returned (see screen shot below for details).

Since the new function input will usually be much more convenient than the original version, it has been named ArcSpline, and the original function has been renamed ArcSpline2.

Input and output for an asymmetric I section with varying radius fillets:

Output with Out = 1:

Posted in Coordinate Geometry, Excel, Maths, Newton, UDFs, VBA | Tagged , , , , | Leave a comment

Using Redim and 3DFrame

I recently received a query about the 3DFrame spreadsheet failing to run.  The problem was that the code was trying to Redim an array that had not been previously created with a Dim statement.  This does not cause a problem with Excel versions up to 2003, and from 2013 to date, but in some cases in Excel 2007 and 2010 the routine will not compile.

The solution is simply to ensure that all arrays are created with a Dim statement, before you try to Redim (which is a good idea even if your Excel version doesn’t require it), but in researching this problem I found two rather surprising things about how it was reported on the Internet:

  • A Google search on “Excel vba redim changed 2013 compile error” (without the “”) only came up with one relevant link, several pages down (at Daily Dose of Excel).
  • The relevant bit was a comment to the main article that I had made myself back in 2009!

The new version of 3DFrame can be downloaded from:

3DFrame.zip

or (as always) from the Downloads page here.

Posted in Excel, Frame Analysis, VBA | Tagged , , , | 1 Comment

Using VBA Evaluate as an Array Function

I recently discovered from a thread at  Chandoo’s Excel Forum that the VBA Evaluate function can be used as an array function.  As a simple example:
Range(“A11:A16”).Value = Evaluate(“= B11:B16 + C11:C16”)
will add the values in columns B and C, and return to column A.

This should not have come as a surprise, since Charles Williams mentioned it in his Excel Blog: Evaluate Functions and Formulas fun: How to make Excel’s Evaluate method twice as fast.  As a rather more useful example than the one above, I have looked at options for calculating the distance between lists of pairs of coordinates.  The code below shows four subroutines that read X and Y coordinates from a specified 4 column range, and return the distance between the two points on each row to the right of the table.

A sample spreadsheet with full open source code and examples may be downloaded from:

EvalDist.xlsb

Sub Distance()
With Sheet1.Range("B12").CurrentRegion.Columns
   .Item(6).Value2 = .Parent.Evaluate("=((" & .Item(3).Address & " - " & .Item(1).Address & ")^2 + (" & .Item(4).Address & "-" & .Item(2).Address & ")^2)^0.5")
End With

End Sub


Sub Distance2()
Dim Col1 As String, Col2 As String, Col3 As String, Col4 As String

With Sheet1.Range("B12").CurrentRegion.Columns
    Col1 = "sheet1!" & .Item(1).Address
    Col2 = "sheet1!" & .Item(2).Address
    Col3 = "sheet1!" & .Item(3).Address
    Col4 = "sheet1!" & .Item(4).Address
   .Item(6).Value2 = Evaluate("=((" & Col3 & " - " & Col1 & ")^2 + (" & Col4 & "-" & Col2 & ")^2)^0.5")
End With

End Sub

Sub Distance3()
Dim XYData As Range
Dim Col1 As String, Col2 As String, Col3 As String, Col4 As String

Set XYData = Range("sheet1!B12:B111")
With XYData.Columns
     Col1 = .Item(1).Address
     Col2 = .Item(2).Address
     Col3 = .Item(3).Address
     Col4 = .Item(4).Address
     
    .Item(6).Value2 = .Parent.Evaluate("=((" & Col3 & " - " & Col1 & ")^2 + (" & Col4 & "-" & Col2 & ")^2)^0.5")
End With

End Sub

Sub Distance4()
Dim XYData As Range, Res As Variant
Dim Col1 As String, Col2 As String, Col3 As String, Col4 As String

Set XYData = Range("sheet1!B12:B111")

With XYData.Columns
     Col1 = .Item(1).Address
     Col2 = .Item(2).Address
     Col3 = .Item(3).Address
     Col4 = .Item(4).Address
     
    Res = .Parent.Evaluate("=((" & Col3 & " - " & Col1 & ")^2 + (" & Col4 & "-" & Col2 & ")^2)^0.5")
.Item(6).Value2 = Res

End With
End Sub

In the first and third routine the Evaluate function is preceded by .Parent, which ensures that the addresses are treated as being on the same sheet as the range specified in the “With” statement.  If this is omitted the addresses will be treated as being on whatever sheet is active when the routine is called.  An alternative is to specify the sheet name with each range (as in Distance2 above).  The fourth function is as Distance3, but the Evaluate results were written to an array for each iteration, and only written back to the spreadsheet once, after the last iteration.  Benchmark results are shown below for these four routines with a range of column lengths and iterations:

Evaluate can also be used in this way from a user defined function (UDF). The code below shows three alternatives.

Function DistF(XYData As Variant)
Dim DistA() As Double, i As Long, NRows As Long, j As Long

XYData = XYData.Value2

NRows = UBound(XYData)
ReDim DistA(1 To NRows, 1 To 1)

    For j = 1 To NRows
        DistA(j, 1) = ((XYData(j, 3) - XYData(j, 1)) ^ 2 + (XYData(j, 4) - XYData(j, 2)) ^ 2) ^ 0.5
    Next j

DistF = DistA
End Function

Function DistF2(XYData As Range)
Dim DistA As Variant
Dim Col1 As String, Col2 As String, Col3 As String, Col4 As String

With XYData.Columns
     Col1 = .Item(1).Address
     Col2 = .Item(2).Address
     Col3 = .Item(3).Address
     Col4 = .Item(4).Address

    DistA = .Parent.Evaluate("=((" & Col3 & " - " & Col1 & ")^2 + (" & Col4 & "-" & Col2 & ")^2)^0.5")
End With

DistF2 = DistA
End Function

Function DistF3(XY_1 As Range, XY_2 As Range)
Dim DistA As Variant
Dim Col1 As String, Col2 As String, Col3 As String, Col4 As String, EvalTxt As String

With XY_1.Columns
     Col1 = .Item(1).Address
     Col2 = .Item(2).Address
End With
With XY_2.Columns
     Col3 = .Item(1).Address
     Col4 = .Item(2).Address
    EvalTxt = "=((" & Col3 & " - " & Col1 & ")^2 + (" & Col4 & "-" & Col2 & ")^2)^0.5"

    DistA = .Parent.Evaluate(EvalTxt)
End With

DistF3 = DistA
End Function

The first does not use Evaluate, converting the input data to a variant array, then looping through each row, writing the results to an array which is returned to the spreadsheet at completion.  The second is similar to Option 3 in the subroutines, except the results are written to an array, which is returned at completion.  The third option has two separate input arrays, so the function can be used on lists of coordinates that are not in adjacent columns.  It also creates the string to be evaluated in a separate operation, which makes checking of the text easier.  Benchmark results for the three functions are shown below:

The two functions using evaluate had very similar performance, and were 2-3 times faster than the routine that looped through the coordinate arrays. They were also faster than the subroutines, probably because the time do not include the time to write the results to the spreadsheet.

Posted in Arrays, Coordinate Geometry, Excel, Maths, UDFs, VBA | Tagged , , , , | 2 Comments